Base | Representation |
---|---|
bin | 1111101110000010010… |
… | …01100111011101011101 |
3 | 1220122010021221202122221 |
4 | 13313001021213131131 |
5 | 32322122011414423 |
6 | 1052042422305341 |
7 | 54010315311331 |
oct | 7670111473535 |
9 | 1818107852587 |
10 | 540111435613 |
11 | 199072908792 |
12 | 88816288251 |
13 | 3bc17318c69 |
14 | 1c1da51b7c1 |
15 | e0b22cce5d |
hex | 7dc126775d |
540111435613 has 2 divisors, whose sum is σ = 540111435614. Its totient is φ = 540111435612.
The previous prime is 540111435587. The next prime is 540111435671. The reversal of 540111435613 is 316534111045.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 521338873444 + 18772562169 = 722038^2 + 137013^2 .
It is a cyclic number.
It is not a de Polignac number, because 540111435613 - 25 = 540111435581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540111435683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270055717806 + 270055717807.
It is an arithmetic number, because the mean of its divisors is an integer number (270055717807).
Almost surely, 2540111435613 is an apocalyptic number.
It is an amenable number.
540111435613 is a deficient number, since it is larger than the sum of its proper divisors (1).
540111435613 is an equidigital number, since it uses as much as digits as its factorization.
540111435613 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 540111435613 its reverse (316534111045), we get a palindrome (856645546658).
The spelling of 540111435613 in words is "five hundred forty billion, one hundred eleven million, four hundred thirty-five thousand, six hundred thirteen".
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