Base | Representation |
---|---|
bin | 111101011001110101110111… |
… | …0000110110110001010011110 |
3 | 2121211101022212101020102102102 |
4 | 1322303223232012312022132 |
5 | 1031243204030400111220 |
6 | 5152420344041525102 |
7 | 221523620244215045 |
oct | 17263535606661236 |
9 | 2554338771212372 |
10 | 540113312113310 |
11 | 147107850a65781 |
12 | 506b16b34a3792 |
13 | 1a24b60b6bc0c0 |
14 | 97538a396955c |
15 | 42698c03a9775 |
hex | 1eb3aee1b629e |
540113312113310 has 64 divisors (see below), whose sum is σ = 1059703326968832. Its totient is φ = 197005108722816.
The previous prime is 540113312113307. The next prime is 540113312113391. The reversal of 540113312113310 is 13311213311045.
It is a super-2 number, since 2×5401133121133102 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 112089917 + ... + 116809143.
It is an arithmetic number, because the mean of its divisors is an integer number (16557864483888).
Almost surely, 2540113312113310 is an apocalyptic number.
540113312113310 is a deficient number, since it is larger than the sum of its proper divisors (519590014855522).
540113312113310 is a wasteful number, since it uses less digits than its factorization.
540113312113310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4729937.
The product of its (nonzero) digits is 3240, while the sum is 29.
Adding to 540113312113310 its reverse (13311213311045), we get a palindrome (553424525424355).
The spelling of 540113312113310 in words is "five hundred forty trillion, one hundred thirteen billion, three hundred twelve million, one hundred thirteen thousand, three hundred ten".
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