Base | Representation |
---|---|
bin | 11000100011111101011111… |
… | …01010010110010010000000 |
3 | 21002020111211100122201122211 |
4 | 30101332233222112102000 |
5 | 24034413401140030222 |
6 | 310512502200511504 |
7 | 14243151461145343 |
oct | 1421765752262200 |
9 | 232214740581584 |
10 | 54012160861312 |
11 | 16234479791865 |
12 | 6083b0347b594 |
13 | 241a42bab5a24 |
14 | d4a2b9a7a45a |
15 | 639ea8563277 |
hex | 311fafa96480 |
54012160861312 has 16 divisors (see below), whose sum is σ = 107602351716150. Its totient is φ = 27006080430592.
The previous prime is 54012160861283. The next prime is 54012160861333. The reversal of 54012160861312 is 21316806121045.
It can be written as a sum of positive squares in only one way, i.e., 47312056397376 + 6700104463936 = 6878376^2 + 2588456^2 .
It is a tau number, because it is divible by the number of its divisors (16).
It is a super-2 number, since 2×540121608613122 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210985003237 + ... + 210985003492.
Almost surely, 254012160861312 is an apocalyptic number.
It is an amenable number.
54012160861312 is a deficient number, since it is larger than the sum of its proper divisors (53590190854838).
54012160861312 is an equidigital number, since it uses as much as digits as its factorization.
54012160861312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 421970006743 (or 421970006731 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 40.
Adding to 54012160861312 its reverse (21316806121045), we get a palindrome (75328966982357).
The spelling of 54012160861312 in words is "fifty-four trillion, twelve billion, one hundred sixty million, eight hundred sixty-one thousand, three hundred twelve".
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