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54013391 is a prime number
BaseRepresentation
bin1100111000001…
…0110111001111
310202122011102222
43032002313033
5102311412031
65205405555
71224051305
oct316026717
9122564388
1054013391
1128542073
12161098bb
13b2620b3
147260275
154b1de7b
hex3382dcf

54013391 has 2 divisors, whose sum is σ = 54013392. Its totient is φ = 54013390.

The previous prime is 54013381. The next prime is 54013417. The reversal of 54013391 is 19331045.

It is an a-pointer prime, because the next prime (54013417) can be obtained adding 54013391 to its sum of digits (26).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 54013391 - 210 = 54012367 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 54013391.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54013381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27006695 + 27006696.

It is an arithmetic number, because the mean of its divisors is an integer number (27006696).

Almost surely, 254013391 is an apocalyptic number.

54013391 is a deficient number, since it is larger than the sum of its proper divisors (1).

54013391 is an equidigital number, since it uses as much as digits as its factorization.

54013391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 26.

The square root of 54013391 is about 7349.3803140129. The cubic root of 54013391 is about 378.0075560950.

It can be divided in two parts, 540 and 13391, that added together give a palindrome (13931).

The spelling of 54013391 in words is "fifty-four million, thirteen thousand, three hundred ninety-one".