Base | Representation |
---|---|
bin | 11000100100001101000111… |
… | …10010001100001011101111 |
3 | 21002021022111010011121112102 |
4 | 30102012203302030023233 |
5 | 24040033042142300403 |
6 | 310520410533525315 |
7 | 14243566424464112 |
oct | 1422064362141357 |
9 | 232238433147472 |
10 | 54020551525103 |
11 | 16237a95028749 |
12 | 60856654a383b |
13 | 241b16824ba47 |
14 | d4a874198579 |
15 | 63a2e9ecab88 |
hex | 3121a3c8c2ef |
54020551525103 has 2 divisors, whose sum is σ = 54020551525104. Its totient is φ = 54020551525102.
The previous prime is 54020551525063. The next prime is 54020551525181. The reversal of 54020551525103 is 30152515502045.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54020551525103 - 218 = 54020551262959 is a prime.
It is a super-3 number, since 3×540205515251033 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54020551585103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27010275762551 + 27010275762552.
It is an arithmetic number, because the mean of its divisors is an integer number (27010275762552).
Almost surely, 254020551525103 is an apocalyptic number.
54020551525103 is a deficient number, since it is larger than the sum of its proper divisors (1).
54020551525103 is an equidigital number, since it uses as much as digits as its factorization.
54020551525103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150000, while the sum is 38.
The spelling of 54020551525103 in words is "fifty-four trillion, twenty billion, five hundred fifty-one million, five hundred twenty-five thousand, one hundred three".
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