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5402542101037 is a prime number
BaseRepresentation
bin100111010011110000010…
…0110100101001000101101
3201010110220110002121110021
41032213200212211020231
51202003401234213122
615253521002442141
71065215013110344
oct116474046451055
921113813077407
105402542101037
1117a3229199004
12733070503351
133025c42829b3
141496ad3d8b5b
15957ec3b01c7
hex4e9e09a522d

5402542101037 has 2 divisors, whose sum is σ = 5402542101038. Its totient is φ = 5402542101036.

The previous prime is 5402542101029. The next prime is 5402542101049. The reversal of 5402542101037 is 7301012452045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5353235454436 + 49306646601 = 2313706^2 + 222051^2 .

It is a cyclic number.

It is not a de Polignac number, because 5402542101037 - 23 = 5402542101029 is a prime.

It is a super-2 number, since 2×54025421010372 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5402542100993 and 5402542101011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5402542101637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2701271050518 + 2701271050519.

It is an arithmetic number, because the mean of its divisors is an integer number (2701271050519).

Almost surely, 25402542101037 is an apocalyptic number.

It is an amenable number.

5402542101037 is a deficient number, since it is larger than the sum of its proper divisors (1).

5402542101037 is an equidigital number, since it uses as much as digits as its factorization.

5402542101037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33600, while the sum is 34.

The spelling of 5402542101037 in words is "five trillion, four hundred two billion, five hundred forty-two million, one hundred one thousand, thirty-seven".