Base | Representation |
---|---|
bin | 11000100101001010100000… |
… | …11000110100011101000110 |
3 | 21002101110120012022111022112 |
4 | 30102211100120310131012 |
5 | 24041103043044310000 |
6 | 310543501325301022 |
7 | 14246144264000435 |
oct | 1422452030643506 |
9 | 232343505274275 |
10 | 54053512103750 |
11 | 1624aa69457295 |
12 | 608bb23a04772 |
13 | 24212bbaa5013 |
14 | d4c2bd8a711c |
15 | 63b0c89ad235 |
hex | 312950634746 |
54053512103750 has 20 divisors (see below), whose sum is σ = 101317903089612. Its totient is φ = 21621404841000.
The previous prime is 54053512103719. The next prime is 54053512103771. The reversal of 54053512103750 is 5730121535045.
It is a junction number, because it is equal to n+sod(n) for n = 54053512103698 and 54053512103707.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 21621403592 + ... + 21621406091.
Almost surely, 254053512103750 is an apocalyptic number.
54053512103750 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
54053512103750 is a deficient number, since it is larger than the sum of its proper divisors (47264390985862).
54053512103750 is an equidigital number, since it uses as much as digits as its factorization.
54053512103750 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43242809705 (or 43242809690 counting only the distinct ones).
The product of its (nonzero) digits is 315000, while the sum is 41.
Adding to 54053512103750 its reverse (5730121535045), we get a palindrome (59783633638795).
The spelling of 54053512103750 in words is "fifty-four trillion, fifty-three billion, five hundred twelve million, one hundred three thousand, seven hundred fifty".
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