Base | Representation |
---|---|
bin | 1111101110111011010… |
… | …11101011010000100101 |
3 | 1220200100122200202120212 |
4 | 13313131223223100211 |
5 | 32324112033013432 |
6 | 1052202122305205 |
7 | 54025220153426 |
oct | 7673553532045 |
9 | 1820318622525 |
10 | 540590126117 |
11 | 19929903aa78 |
12 | 8892a658205 |
13 | 3bc9254c892 |
14 | 1c243d2764d |
15 | e0de3372b2 |
hex | 7dddaeb425 |
540590126117 has 2 divisors, whose sum is σ = 540590126118. Its totient is φ = 540590126116.
The previous prime is 540590126101. The next prime is 540590126123. The reversal of 540590126117 is 711621095045.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 531373934116 + 9216192001 = 728954^2 + 96001^2 .
It is a cyclic number.
It is not a de Polignac number, because 540590126117 - 24 = 540590126101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (540590126137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270295063058 + 270295063059.
It is an arithmetic number, because the mean of its divisors is an integer number (270295063059).
Almost surely, 2540590126117 is an apocalyptic number.
It is an amenable number.
540590126117 is a deficient number, since it is larger than the sum of its proper divisors (1).
540590126117 is an equidigital number, since it uses as much as digits as its factorization.
540590126117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 41.
The spelling of 540590126117 in words is "five hundred forty billion, five hundred ninety million, one hundred twenty-six thousand, one hundred seventeen".
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