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54065278899133 is a prime number
BaseRepresentation
bin11000100101100000011011…
…01111100101001110111101
321002102120221020121122001221
430102300031233211032331
524041301142344233013
6310553125104433341
714250042004053355
oct1422601557451675
9232376836548057
1054065278899133
1116254a57506877
126092268618851
132422445827a38
14d4cab853bb65
1563b566a1608d
hex312c0dbe53bd

54065278899133 has 2 divisors, whose sum is σ = 54065278899134. Its totient is φ = 54065278899132.

The previous prime is 54065278899061. The next prime is 54065278899157. The reversal of 54065278899133 is 33199887256045.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53832933690649 + 232345208484 = 7337093^2 + 482022^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54065278899133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54065278891133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27032639449566 + 27032639449567.

It is an arithmetic number, because the mean of its divisors is an integer number (27032639449567).

It is a 1-persistent number, because it is pandigital, but 2⋅54065278899133 = 108130557798266 is not.

Almost surely, 254065278899133 is an apocalyptic number.

It is an amenable number.

54065278899133 is a deficient number, since it is larger than the sum of its proper divisors (1).

54065278899133 is an equidigital number, since it uses as much as digits as its factorization.

54065278899133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 391910400, while the sum is 70.

The spelling of 54065278899133 in words is "fifty-four trillion, sixty-five billion, two hundred seventy-eight million, eight hundred ninety-nine thousand, one hundred thirty-three".