Base | Representation |
---|---|
bin | 11000100110100001101101… |
… | …10001111011110101110011 |
3 | 21002112221101211000201221021 |
4 | 30103100312301323311303 |
5 | 24042334432220321433 |
6 | 311021202553440311 |
7 | 14252422353035125 |
oct | 1423206661736563 |
9 | 232487354021837 |
10 | 54100327120243 |
11 | 162689022a3068 |
12 | 609900a110097 |
13 | 242583ca33201 |
14 | d506811db215 |
15 | 63c41891e22d |
hex | 313436c7bd73 |
54100327120243 has 2 divisors, whose sum is σ = 54100327120244. Its totient is φ = 54100327120242.
The previous prime is 54100327120241. The next prime is 54100327120283. The reversal of 54100327120243 is 34202172300145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54100327120243 - 21 = 54100327120241 is a prime.
Together with 54100327120241, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 54100327120199 and 54100327120208.
It is not a weakly prime, because it can be changed into another prime (54100327120241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27050163560121 + 27050163560122.
It is an arithmetic number, because the mean of its divisors is an integer number (27050163560122).
Almost surely, 254100327120243 is an apocalyptic number.
54100327120243 is a deficient number, since it is larger than the sum of its proper divisors (1).
54100327120243 is an equidigital number, since it uses as much as digits as its factorization.
54100327120243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 54100327120243 its reverse (34202172300145), we get a palindrome (88302499420388).
The spelling of 54100327120243 in words is "fifty-four trillion, one hundred billion, three hundred twenty-seven million, one hundred twenty thousand, two hundred forty-three".
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