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54104115433393 is a prime number
BaseRepresentation
bin11000100110101000110001…
…00101001100111110110001
321002120022011211101222121201
430103110120211030332301
524042420212022332033
6311023030522251201
714252615263130644
oct1423243045147661
9232508154358551
1054104115433393
111626a476741883
1260998a6956b01
132425cc483801c
14d509203a9a5b
1563c58b2cc47d
hex31351894cfb1

54104115433393 has 2 divisors, whose sum is σ = 54104115433394. Its totient is φ = 54104115433392.

The previous prime is 54104115433369. The next prime is 54104115433439. The reversal of 54104115433393 is 39333451140145.

It is an a-pointer prime, because the next prime (54104115433439) can be obtained adding 54104115433393 to its sum of digits (46).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48406694930064 + 5697420503329 = 6957492^2 + 2386927^2 .

It is a cyclic number.

It is not a de Polignac number, because 54104115433393 - 245 = 18919743344561 is a prime.

It is a super-2 number, since 2×541041154333932 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (54104115413393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27052057716696 + 27052057716697.

It is an arithmetic number, because the mean of its divisors is an integer number (27052057716697).

Almost surely, 254104115433393 is an apocalyptic number.

It is an amenable number.

54104115433393 is a deficient number, since it is larger than the sum of its proper divisors (1).

54104115433393 is an equidigital number, since it uses as much as digits as its factorization.

54104115433393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 46.

The spelling of 54104115433393 in words is "fifty-four trillion, one hundred four billion, one hundred fifteen million, four hundred thirty-three thousand, three hundred ninety-three".