Base | Representation |
---|---|
bin | 11000100110101000110001… |
… | …00101001100111111011111 |
3 | 21002120022011211101222200102 |
4 | 30103110120211030333133 |
5 | 24042420212022332224 |
6 | 311023030522251315 |
7 | 14252615263131041 |
oct | 1423243045147737 |
9 | 232508154358612 |
10 | 54104115433439 |
11 | 1626a476741915 |
12 | 60998a6956b3b |
13 | 2425cc4838056 |
14 | d509203a9a91 |
15 | 63c58b2cc4ae |
hex | 31351894cfdf |
54104115433439 has 2 divisors, whose sum is σ = 54104115433440. Its totient is φ = 54104115433438.
The previous prime is 54104115433393. The next prime is 54104115433453. The reversal of 54104115433439 is 93433451140145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54104115433439 - 216 = 54104115367903 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54104115433393 and 54104115433402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54104115433499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27052057716719 + 27052057716720.
It is an arithmetic number, because the mean of its divisors is an integer number (27052057716720).
Almost surely, 254104115433439 is an apocalyptic number.
54104115433439 is a deficient number, since it is larger than the sum of its proper divisors (1).
54104115433439 is an equidigital number, since it uses as much as digits as its factorization.
54104115433439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1555200, while the sum is 47.
The spelling of 54104115433439 in words is "fifty-four trillion, one hundred four billion, one hundred fifteen million, four hundred thirty-three thousand, four hundred thirty-nine".
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