Base | Representation |
---|---|
bin | 11000100110111010010001… |
… | …00100111111101101110011 |
3 | 21002121012102121002220202202 |
4 | 30103131020210333231303 |
5 | 24043043432204320034 |
6 | 311031223101533415 |
7 | 14253400144655414 |
oct | 1423351044775563 |
9 | 232535377086682 |
10 | 54113510620019 |
11 | 16273458010624 |
12 | 609b68927426b |
13 | 2426b61132a56 |
14 | d5117209180b |
15 | 63c93b01b47e |
hex | 31374893fb73 |
54113510620019 has 2 divisors, whose sum is σ = 54113510620020. Its totient is φ = 54113510620018.
The previous prime is 54113510620003. The next prime is 54113510620021. The reversal of 54113510620019 is 91002601531145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54113510620019 - 24 = 54113510620003 is a prime.
It is a super-2 number, since 2×541135106200192 (a number of 28 digits) contains 22 as substring.
Together with 54113510620021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (54113510620069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27056755310009 + 27056755310010.
It is an arithmetic number, because the mean of its divisors is an integer number (27056755310010).
Almost surely, 254113510620019 is an apocalyptic number.
54113510620019 is a deficient number, since it is larger than the sum of its proper divisors (1).
54113510620019 is an equidigital number, since it uses as much as digits as its factorization.
54113510620019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 38.
The spelling of 54113510620019 in words is "fifty-four trillion, one hundred thirteen billion, five hundred ten million, six hundred twenty thousand, nineteen".
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