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541331340541 is a prime number
BaseRepresentation
bin1111110000010011101…
…11001011110011111101
31220202021022102100121221
413320021313023303331
532332121310344131
61052403441153341
754052460321425
oct7701167136375
91822238370557
10541331340541
1119963947a382
1288ab692b851
133c07cc8c4b4
141c2b454d485
15e13444b411
hex7e09dcbcfd

541331340541 has 2 divisors, whose sum is σ = 541331340542. Its totient is φ = 541331340540.

The previous prime is 541331340523. The next prime is 541331340551. The reversal of 541331340541 is 145043133145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 447708192100 + 93623148441 = 669110^2 + 305979^2 .

It is a cyclic number.

It is not a de Polignac number, because 541331340541 - 25 = 541331340509 is a prime.

It is a super-2 number, since 2×5413313405412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 541331340497 and 541331340506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541331340551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270665670270 + 270665670271.

It is an arithmetic number, because the mean of its divisors is an integer number (270665670271).

Almost surely, 2541331340541 is an apocalyptic number.

It is an amenable number.

541331340541 is a deficient number, since it is larger than the sum of its proper divisors (1).

541331340541 is an equidigital number, since it uses as much as digits as its factorization.

541331340541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 541331340541 its reverse (145043133145), we get a palindrome (686374473686).

The spelling of 541331340541 in words is "five hundred forty-one billion, three hundred thirty-one million, three hundred forty thousand, five hundred forty-one".