Base | Representation |
---|---|
bin | 11000100111110101000110… |
… | …11101101011100011111101 |
3 | 21002201012222010110212012111 |
4 | 30103322203131223203331 |
5 | 24044103131122401224 |
6 | 311053525440134021 |
7 | 14255566025655655 |
oct | 1423724335534375 |
9 | 232635863425174 |
10 | 54145100200189 |
11 | 16285898559779 |
12 | 60a5824607311 |
13 | 2429b26922c1b |
14 | d528cb67b365 |
15 | 63d689486d94 |
hex | 313ea376b8fd |
54145100200189 has 2 divisors, whose sum is σ = 54145100200190. Its totient is φ = 54145100200188.
The previous prime is 54145100200171. The next prime is 54145100200253. The reversal of 54145100200189 is 98100200154145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53621129796025 + 523970404164 = 7322645^2 + 723858^2 .
It is a cyclic number.
It is not a de Polignac number, because 54145100200189 - 25 = 54145100200157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54145100207189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27072550100094 + 27072550100095.
It is an arithmetic number, because the mean of its divisors is an integer number (27072550100095).
Almost surely, 254145100200189 is an apocalyptic number.
It is an amenable number.
54145100200189 is a deficient number, since it is larger than the sum of its proper divisors (1).
54145100200189 is an equidigital number, since it uses as much as digits as its factorization.
54145100200189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 40.
The spelling of 54145100200189 in words is "fifty-four trillion, one hundred forty-five billion, one hundred million, two hundred thousand, one hundred eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •