Base | Representation |
---|---|
bin | 11000100111110101000110… |
… | …11101101011100100111101 |
3 | 21002201012222010110212021212 |
4 | 30103322203131223210331 |
5 | 24044103131122402003 |
6 | 311053525440134205 |
7 | 14255566025656106 |
oct | 1423724335534475 |
9 | 232635863425255 |
10 | 54145100200253 |
11 | 16285898559827 |
12 | 60a5824607365 |
13 | 2429b26922c6a |
14 | d528cb67b3ad |
15 | 63d689486dd8 |
hex | 313ea376b93d |
54145100200253 has 2 divisors, whose sum is σ = 54145100200254. Its totient is φ = 54145100200252.
The previous prime is 54145100200189. The next prime is 54145100200313. The reversal of 54145100200253 is 35200200154145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49324958987929 + 4820141212324 = 7023173^2 + 2195482^2 .
It is a cyclic number.
It is not a de Polignac number, because 54145100200253 - 26 = 54145100200189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54145100200753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27072550100126 + 27072550100127.
It is an arithmetic number, because the mean of its divisors is an integer number (27072550100127).
Almost surely, 254145100200253 is an apocalyptic number.
It is an amenable number.
54145100200253 is a deficient number, since it is larger than the sum of its proper divisors (1).
54145100200253 is an equidigital number, since it uses as much as digits as its factorization.
54145100200253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 54145100200253 its reverse (35200200154145), we get a palindrome (89345300354398).
The spelling of 54145100200253 in words is "fifty-four trillion, one hundred forty-five billion, one hundred million, two hundred thousand, two hundred fifty-three".
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