Search a number
-
+
5414540323421 is a prime number
BaseRepresentation
bin100111011001010101111…
…0000001010101001011101
3201011121212121212110101002
41032302223300022221131
51202202434310322141
615303223330200045
71066121233241465
oct116625360125135
921147777773332
105414540323421
1117a8325946079
1273545a723025
13303786c44378
1414a0caab2ba5
1595ca08cde9b
hex4ecabc0aa5d

5414540323421 has 2 divisors, whose sum is σ = 5414540323422. Its totient is φ = 5414540323420.

The previous prime is 5414540323399. The next prime is 5414540323427. The reversal of 5414540323421 is 1243230454145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4784325036100 + 630215287321 = 2187310^2 + 793861^2 .

It is a cyclic number.

It is not a de Polignac number, because 5414540323421 - 238 = 5139662416477 is a prime.

It is a super-2 number, since 2×54145403234212 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5414540323427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707270161710 + 2707270161711.

It is an arithmetic number, because the mean of its divisors is an integer number (2707270161711).

Almost surely, 25414540323421 is an apocalyptic number.

It is an amenable number.

5414540323421 is a deficient number, since it is larger than the sum of its proper divisors (1).

5414540323421 is an equidigital number, since it uses as much as digits as its factorization.

5414540323421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 5414540323421 its reverse (1243230454145), we get a palindrome (6657770777566).

The spelling of 5414540323421 in words is "five trillion, four hundred fourteen billion, five hundred forty million, three hundred twenty-three thousand, four hundred twenty-one".