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541841965037 is a prime number
BaseRepresentation
bin1111110001010000100…
…11000011111111101101
31220210120220020202202022
413320220103003333231
532334143020340122
61052530241435525
754101230465532
oct7705023037755
91823526222668
10541841965037
1119988073309a
128901993bba5
133c1319c4479
141c3222acd89
15e1641b2642
hex7e284c3fed

541841965037 has 2 divisors, whose sum is σ = 541841965038. Its totient is φ = 541841965036.

The previous prime is 541841964977. The next prime is 541841965079. The reversal of 541841965037 is 730569148145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 405547354276 + 136294610761 = 636826^2 + 369181^2 .

It is a cyclic number.

It is not a de Polignac number, because 541841965037 - 26 = 541841964973 is a prime.

It is a super-2 number, since 2×5418419650372 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 541841965037.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541841965937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270920982518 + 270920982519.

It is an arithmetic number, because the mean of its divisors is an integer number (270920982519).

Almost surely, 2541841965037 is an apocalyptic number.

It is an amenable number.

541841965037 is a deficient number, since it is larger than the sum of its proper divisors (1).

541841965037 is an equidigital number, since it uses as much as digits as its factorization.

541841965037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3628800, while the sum is 53.

The spelling of 541841965037 in words is "five hundred forty-one billion, eight hundred forty-one million, nine hundred sixty-five thousand, thirty-seven".