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541941117419549 is a prime number
BaseRepresentation
bin111101100111001000111111…
…1110010110000000000011101
32122001212001202021101111102002
41323032101333302300000131
51032013130402024411144
65200340151245012045
7222102645046035641
oct17316217762600035
92561761667344362
10541941117419549
11147751a344534a1
125094799b854025
131a351a9c405023
1497b81390c6c21
15429c1eb01c14e
hex1ece47fcb001d

541941117419549 has 2 divisors, whose sum is σ = 541941117419550. Its totient is φ = 541941117419548.

The previous prime is 541941117419503. The next prime is 541941117419551. The reversal of 541941117419549 is 945914711149145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 525579375568324 + 16361741851225 = 22925518^2 + 4044965^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-541941117419549 is a prime.

Together with 541941117419551, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (541941117419249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270970558709774 + 270970558709775.

It is an arithmetic number, because the mean of its divisors is an integer number (270970558709775).

Almost surely, 2541941117419549 is an apocalyptic number.

It is an amenable number.

541941117419549 is a deficient number, since it is larger than the sum of its proper divisors (1).

541941117419549 is an equidigital number, since it uses as much as digits as its factorization.

541941117419549 is an evil number, because the sum of its binary digits is even.

The product of its digits is 32659200, while the sum is 65.

The spelling of 541941117419549 in words is "five hundred forty-one trillion, nine hundred forty-one billion, one hundred seventeen million, four hundred nineteen thousand, five hundred forty-nine".