Base | Representation |
---|---|
bin | 11000101001011101110111… |
… | …01101010000010110011111 |
3 | 21002220121010200102110210122 |
4 | 30110232323231100112133 |
5 | 24101013321411323241 |
6 | 311135430314425155 |
7 | 14262626525142236 |
oct | 1424567355202637 |
9 | 232817120373718 |
10 | 54201341511071 |
11 | 162a7729290a97 |
12 | 60b46bb7321bb |
13 | 243221a74b0c1 |
14 | d55504c73b1d |
15 | 63ed7bc2e04b |
hex | 314bbbb5059f |
54201341511071 has 2 divisors, whose sum is σ = 54201341511072. Its totient is φ = 54201341511070.
The previous prime is 54201341511059. The next prime is 54201341511113. The reversal of 54201341511071 is 17011514310245.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54201341511071 - 26 = 54201341511007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54201341514071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27100670755535 + 27100670755536.
It is an arithmetic number, because the mean of its divisors is an integer number (27100670755536).
Almost surely, 254201341511071 is an apocalyptic number.
54201341511071 is a deficient number, since it is larger than the sum of its proper divisors (1).
54201341511071 is an equidigital number, since it uses as much as digits as its factorization.
54201341511071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 35.
The spelling of 54201341511071 in words is "fifty-four trillion, two hundred one billion, three hundred forty-one million, five hundred eleven thousand, seventy-one".
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