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54201341511113 is a prime number
BaseRepresentation
bin11000101001011101110111…
…01101010000010111001001
321002220121010200102110212012
430110232323231100113021
524101013321411323423
6311135430314425305
714262626525142326
oct1424567355202711
9232817120373765
1054201341511113
11162a7729291025
1260b46bb732235
13243221a74b124
14d55504c73b4d
1563ed7bc2e078
hex314bbbb505c9

54201341511113 has 2 divisors, whose sum is σ = 54201341511114. Its totient is φ = 54201341511112.

The previous prime is 54201341511071. The next prime is 54201341511179. The reversal of 54201341511113 is 31111514310245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37768436233609 + 16432905277504 = 6145603^2 + 4053752^2 .

It is a cyclic number.

It is not a de Polignac number, because 54201341511113 - 210 = 54201341510089 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 54201341511113.

It is not a weakly prime, because it can be changed into another prime (54201341511313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27100670755556 + 27100670755557.

It is an arithmetic number, because the mean of its divisors is an integer number (27100670755557).

Almost surely, 254201341511113 is an apocalyptic number.

It is an amenable number.

54201341511113 is a deficient number, since it is larger than the sum of its proper divisors (1).

54201341511113 is an equidigital number, since it uses as much as digits as its factorization.

54201341511113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 32.

Adding to 54201341511113 its reverse (31111514310245), we get a palindrome (85312855821358).

The spelling of 54201341511113 in words is "fifty-four trillion, two hundred one billion, three hundred forty-one million, five hundred eleven thousand, one hundred thirteen".