Base | Representation |
---|---|
bin | 11000101001011101110111… |
… | …01101010000010111001001 |
3 | 21002220121010200102110212012 |
4 | 30110232323231100113021 |
5 | 24101013321411323423 |
6 | 311135430314425305 |
7 | 14262626525142326 |
oct | 1424567355202711 |
9 | 232817120373765 |
10 | 54201341511113 |
11 | 162a7729291025 |
12 | 60b46bb732235 |
13 | 243221a74b124 |
14 | d55504c73b4d |
15 | 63ed7bc2e078 |
hex | 314bbbb505c9 |
54201341511113 has 2 divisors, whose sum is σ = 54201341511114. Its totient is φ = 54201341511112.
The previous prime is 54201341511071. The next prime is 54201341511179. The reversal of 54201341511113 is 31111514310245.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37768436233609 + 16432905277504 = 6145603^2 + 4053752^2 .
It is a cyclic number.
It is not a de Polignac number, because 54201341511113 - 210 = 54201341510089 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54201341511113.
It is not a weakly prime, because it can be changed into another prime (54201341511313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27100670755556 + 27100670755557.
It is an arithmetic number, because the mean of its divisors is an integer number (27100670755557).
Almost surely, 254201341511113 is an apocalyptic number.
It is an amenable number.
54201341511113 is a deficient number, since it is larger than the sum of its proper divisors (1).
54201341511113 is an equidigital number, since it uses as much as digits as its factorization.
54201341511113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 54201341511113 its reverse (31111514310245), we get a palindrome (85312855821358).
The spelling of 54201341511113 in words is "fifty-four trillion, two hundred one billion, three hundred forty-one million, five hundred eleven thousand, one hundred thirteen".
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