Base | Representation |
---|---|
bin | 11000101001011101110111… |
… | …10100100100000001001111 |
3 | 21002220121010211000210110121 |
4 | 30110232323310210001033 |
5 | 24101013322404123024 |
6 | 311135430423445411 |
7 | 14262626550341053 |
oct | 1424567364440117 |
9 | 232817124023417 |
10 | 54201343426639 |
11 | 162a772a37a202 |
12 | 60b47002b6867 |
13 | 243221ac6bc86 |
14 | d55505211c63 |
15 | 63ed7beab8e4 |
hex | 314bbbd2404f |
54201343426639 has 2 divisors, whose sum is σ = 54201343426640. Its totient is φ = 54201343426638.
The previous prime is 54201343426619. The next prime is 54201343426651. The reversal of 54201343426639 is 93662434310245.
It is a happy number.
54201343426639 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54201343426639 - 29 = 54201343426127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54201343426619) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27100671713319 + 27100671713320.
It is an arithmetic number, because the mean of its divisors is an integer number (27100671713320).
Almost surely, 254201343426639 is an apocalyptic number.
54201343426639 is a deficient number, since it is larger than the sum of its proper divisors (1).
54201343426639 is an equidigital number, since it uses as much as digits as its factorization.
54201343426639 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11197440, while the sum is 52.
The spelling of 54201343426639 in words is "fifty-four trillion, two hundred one billion, three hundred forty-three million, four hundred twenty-six thousand, six hundred thirty-nine".
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