Base | Representation |
---|---|
bin | 100111011100000001111… |
… | …1010101011101100101101 |
3 | 201012011210000220002201210 |
4 | 1032320003322223230231 |
5 | 1202301300444130131 |
6 | 15310020313425033 |
7 | 1066414305401145 |
oct | 116700372535455 |
9 | 21164700802653 |
10 | 5420314442541 |
11 | 17aa819217249 |
12 | 7365b040b179 |
13 | 3041972939bb |
14 | 14a4b78c3925 |
15 | 95edc799146 |
hex | 4ee03eabb2d |
5420314442541 has 32 divisors (see below), whose sum is σ = 7402224545280. Its totient is φ = 3526426722816.
The previous prime is 5420314442479. The next prime is 5420314442551. The reversal of 5420314442541 is 1452444130245.
It is not a de Polignac number, because 5420314442541 - 211 = 5420314440493 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5420314442541.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5420314442551) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 135905895 + ... + 135945771.
It is an arithmetic number, because the mean of its divisors is an integer number (231319517040).
Almost surely, 25420314442541 is an apocalyptic number.
It is an amenable number.
5420314442541 is a deficient number, since it is larger than the sum of its proper divisors (1981910102739).
5420314442541 is a wasteful number, since it uses less digits than its factorization.
5420314442541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42693.
The product of its (nonzero) digits is 307200, while the sum is 39.
Adding to 5420314442541 its reverse (1452444130245), we get a palindrome (6872758572786).
The spelling of 5420314442541 in words is "five trillion, four hundred twenty billion, three hundred fourteen million, four hundred forty-two thousand, five hundred forty-one".
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