Base | Representation |
---|---|
bin | 11000101001110010101110… |
… | …01101011001110100011101 |
3 | 21002221200001011000000011020 |
4 | 30110321113031121310131 |
5 | 24101204240311412113 |
6 | 311144521444314353 |
7 | 14263504200501600 |
oct | 1424712715316435 |
9 | 232850034000136 |
10 | 54212540341533 |
11 | 16301455783082 |
12 | 60b69060a29b9 |
13 | 24332b39105c2 |
14 | d55c88300337 |
15 | 6402d4e96023 |
hex | 314e57359d1d |
54212540341533 has 96 divisors (see below), whose sum is σ = 89938163220480. Its totient is φ = 28894198798080.
The previous prime is 54212540341517. The next prime is 54212540341559. The reversal of 54212540341533 is 33514304521245.
It is not a de Polignac number, because 54212540341533 - 24 = 54212540341517 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54212540341433) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 42434353 + ... + 43693241.
It is an arithmetic number, because the mean of its divisors is an integer number (936855866880).
Almost surely, 254212540341533 is an apocalyptic number.
It is an amenable number.
54212540341533 is a deficient number, since it is larger than the sum of its proper divisors (35725622878947).
54212540341533 is a wasteful number, since it uses less digits than its factorization.
54212540341533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1259247 (or 1259240 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 54212540341533 its reverse (33514304521245), we get a palindrome (87726844862778).
The spelling of 54212540341533 in words is "fifty-four trillion, two hundred twelve billion, five hundred forty million, three hundred forty-one thousand, five hundred thirty-three".
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