Base | Representation |
---|---|
bin | 110010100001000001… |
… | …111001000101100111 |
3 | 12012000011110020200212 |
4 | 302201001321011213 |
5 | 1342041224012203 |
6 | 40530145530035 |
7 | 3630101615153 |
oct | 624101710547 |
9 | 165004406625 |
10 | 54241235303 |
11 | 210048439a2 |
12 | a61934391b |
13 | 5165655608 |
14 | 28a7b1c063 |
15 | 1626dbc1d8 |
hex | ca1079167 |
54241235303 has 2 divisors, whose sum is σ = 54241235304. Its totient is φ = 54241235302.
The previous prime is 54241235227. The next prime is 54241235309. The reversal of 54241235303 is 30353214245.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54241235303 - 228 = 53972799847 is a prime.
It is a super-2 number, since 2×542412353032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 54241235303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54241235309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27120617651 + 27120617652.
It is an arithmetic number, because the mean of its divisors is an integer number (27120617652).
Almost surely, 254241235303 is an apocalyptic number.
54241235303 is a deficient number, since it is larger than the sum of its proper divisors (1).
54241235303 is an equidigital number, since it uses as much as digits as its factorization.
54241235303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 54241235303 its reverse (30353214245), we get a palindrome (84594449548).
The spelling of 54241235303 in words is "fifty-four billion, two hundred forty-one million, two hundred thirty-five thousand, three hundred three".
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