Base | Representation |
---|---|
bin | 100111011110001111000… |
… | …1111101101100110001011 |
3 | 201012122000010210202201221 |
4 | 1032330132033231212023 |
5 | 1202341001042132001 |
6 | 15312122321222511 |
7 | 1066642552520254 |
oct | 116743617554613 |
9 | 21178003722657 |
10 | 5425051130251 |
11 | 1801829a28895 |
12 | 7374b2791a37 |
13 | 3047706cb7ac |
14 | 14a806a01b2b |
15 | 961b853c1a1 |
hex | 4ef1e3ed98b |
5425051130251 has 2 divisors, whose sum is σ = 5425051130252. Its totient is φ = 5425051130250.
The previous prime is 5425051130249. The next prime is 5425051130281. The reversal of 5425051130251 is 1520311505245.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5425051130251 - 21 = 5425051130249 is a prime.
It is a super-3 number, since 3×54250511302513 (a number of 39 digits) contains 333 as substring.
Together with 5425051130249, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5425051130281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2712525565125 + 2712525565126.
It is an arithmetic number, because the mean of its divisors is an integer number (2712525565126).
Almost surely, 25425051130251 is an apocalyptic number.
5425051130251 is a deficient number, since it is larger than the sum of its proper divisors (1).
5425051130251 is an equidigital number, since it uses as much as digits as its factorization.
5425051130251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 5425051130251 its reverse (1520311505245), we get a palindrome (6945362635496).
The spelling of 5425051130251 in words is "five trillion, four hundred twenty-five billion, fifty-one million, one hundred thirty thousand, two hundred fifty-one".
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