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54251365332053 is a prime number
BaseRepresentation
bin11000101010111011000010…
…10110111111010001010101
321010002101020221001212200002
430111131201112333101111
524102323244011111203
6311214422210501045
714266350256460021
oct1425354126772125
9233071227055602
1054251365332053
11163169694440aa
126102340594785
132436b6040b486
14d57acc805381
1564130872bd88
hex3157615bf455

54251365332053 has 2 divisors, whose sum is σ = 54251365332054. Its totient is φ = 54251365332052.

The previous prime is 54251365331993. The next prime is 54251365332127. The reversal of 54251365332053 is 35023356315245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54066859002289 + 184506329764 = 7353017^2 + 429542^2 .

It is a cyclic number.

It is not a de Polignac number, because 54251365332053 - 220 = 54251364283477 is a prime.

It is a super-2 number, since 2×542513653320532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 54251365331989 and 54251365332007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54251365332953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27125682666026 + 27125682666027.

It is an arithmetic number, because the mean of its divisors is an integer number (27125682666027).

Almost surely, 254251365332053 is an apocalyptic number.

It is an amenable number.

54251365332053 is a deficient number, since it is larger than the sum of its proper divisors (1).

54251365332053 is an equidigital number, since it uses as much as digits as its factorization.

54251365332053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860000, while the sum is 47.

The spelling of 54251365332053 in words is "fifty-four trillion, two hundred fifty-one billion, three hundred sixty-five million, three hundred thirty-two thousand, fifty-three".