Base | Representation |
---|---|
bin | 110010100001101011… |
… | …011101100010011111 |
3 | 12012000220221212212011 |
4 | 302201223131202133 |
5 | 1342102021220021 |
6 | 40531215252051 |
7 | 3630263342353 |
oct | 624153354237 |
9 | 165026855764 |
10 | 54252132511 |
11 | 2100aa07155 |
12 | a620b1a027 |
13 | 516799c675 |
14 | 28a9357463 |
15 | 1627d20de1 |
hex | ca1add89f |
54252132511 has 2 divisors, whose sum is σ = 54252132512. Its totient is φ = 54252132510.
The previous prime is 54252132509. The next prime is 54252132577. The reversal of 54252132511 is 11523125245.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54252132511 - 21 = 54252132509 is a prime.
It is a super-2 number, since 2×542521325112 (a number of 22 digits) contains 22 as substring.
Together with 54252132509, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54252132611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27126066255 + 27126066256.
It is an arithmetic number, because the mean of its divisors is an integer number (27126066256).
Almost surely, 254252132511 is an apocalyptic number.
54252132511 is a deficient number, since it is larger than the sum of its proper divisors (1).
54252132511 is an equidigital number, since it uses as much as digits as its factorization.
54252132511 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12000, while the sum is 31.
Adding to 54252132511 its reverse (11523125245), we get a palindrome (65775257756).
The spelling of 54252132511 in words is "fifty-four billion, two hundred fifty-two million, one hundred thirty-two thousand, five hundred eleven".
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