Base | Representation |
---|---|
bin | 11000101100101100011001… |
… | …01001000100011001000111 |
3 | 21010022012100001210211220001 |
4 | 30112112030221010121013 |
5 | 24104322412041042210 |
6 | 311302405003422131 |
7 | 14303633316424525 |
oct | 1426261451043107 |
9 | 233265301724801 |
10 | 54312221034055 |
11 | 1633a7579477a6 |
12 | 61120a4b24947 |
13 | 243c80b2220ba |
14 | d5aa22ba3315 |
15 | 642bbb15b03a |
hex | 31658ca44647 |
54312221034055 has 32 divisors (see below), whose sum is σ = 70328786393664. Its totient is φ = 40111898351616.
The previous prime is 54312221034017. The next prime is 54312221034107. The reversal of 54312221034055 is 55043012221345.
It is a happy number.
It is not a de Polignac number, because 54312221034055 - 215 = 54312221001287 is a prime.
It is a super-3 number, since 3×543122210340553 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15793272 + ... + 18922258.
It is an arithmetic number, because the mean of its divisors is an integer number (2197774574802).
Almost surely, 254312221034055 is an apocalyptic number.
54312221034055 is a deficient number, since it is larger than the sum of its proper divisors (16016565359609).
54312221034055 is a wasteful number, since it uses less digits than its factorization.
54312221034055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3132915.
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 54312221034055 in words is "fifty-four trillion, three hundred twelve billion, two hundred twenty-one million, thirty-four thousand, fifty-five".
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