5432333441 has 2 divisors, whose sum is σ = 5432333442. Its totient is φ = 5432333440.

The previous prime is 5432333381. The next prime is 5432333443. The reversal of 5432333441 is 1443332345.

5432333441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2959360000 + 2472973441 = 54400^2 + 49729^2 .

It is a cyclic number.

It is not a de Polignac number, because 5432333441 - 2²² = 5428139137 is a prime.

It is a super-2 number, since 2×5432333441² = 59020493228413800962, which contains 22 as substring.

Together with 5432333443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5432333398 and 5432333407.

It is not a weakly prime, because it can be changed into another prime (5432333443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716166720 + 2716166721.

It is an arithmetic number, because the mean of its divisors is an integer number (2716166721).

Almost surely, 2^5432333441 is an apocalyptic number.

It is an amenable number.

5432333441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5432333441 is an equidigital number, since it uses as much as digits as its factorization.

5432333441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 51840, while the sum is 32.

The square root of 5432333441 is about 73704.3651421000. The cubic root of 5432333441 is about 1757.9052903929.

Adding to 5432333441 its reverse (1443332345), we get a palindrome (6875665786).

The spelling of 5432333441 in words is "five billion, four hundred thirty-two million, three hundred thirty-three thousand, four hundred forty-one".