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5434325551217 is a prime number
BaseRepresentation
bin100111100010100011100…
…0010110100100001110001
3201020111221111021011112202
41033011013002310201301
51203013444320114332
615320254504232545
71100421440014403
oct117050702644161
921214844234482
105434325551217
111805759112602
1273926076b755
133055bac91c54
1414b04664cb73
159655c873a62
hex4f1470b4871

5434325551217 has 2 divisors, whose sum is σ = 5434325551218. Its totient is φ = 5434325551216.

The previous prime is 5434325551093. The next prime is 5434325551219. The reversal of 5434325551217 is 7121555234345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3349793099536 + 2084532451681 = 1830244^2 + 1443791^2 .

It is a cyclic number.

It is not a de Polignac number, because 5434325551217 - 222 = 5434321356913 is a prime.

Together with 5434325551219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5434325551219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717162775608 + 2717162775609.

It is an arithmetic number, because the mean of its divisors is an integer number (2717162775609).

Almost surely, 25434325551217 is an apocalyptic number.

It is an amenable number.

5434325551217 is a deficient number, since it is larger than the sum of its proper divisors (1).

5434325551217 is an equidigital number, since it uses as much as digits as its factorization.

5434325551217 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2520000, while the sum is 47.

The spelling of 5434325551217 in words is "five trillion, four hundred thirty-four billion, three hundred twenty-five million, five hundred fifty-one thousand, two hundred seventeen".