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54352362570137 is a prime number
BaseRepresentation
bin11000101101110111001010…
…10000111000000110011001
321010110000221121012011101122
430112323211100320012121
524111002114304221022
6311333044120055025
714306554133024132
oct1426734520700631
9233400847164348
1054352362570137
1116355786786a05
126119a28304475
1324435376cbc08
14d5c950094c89
15643c6a29e742
hex316ee5438199

54352362570137 has 2 divisors, whose sum is σ = 54352362570138. Its totient is φ = 54352362570136.

The previous prime is 54352362570091. The next prime is 54352362570139. The reversal of 54352362570137 is 73107526325345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43799896186201 + 10552466383936 = 6618149^2 + 3248456^2 .

It is a cyclic number.

It is not a de Polignac number, because 54352362570137 - 28 = 54352362569881 is a prime.

Together with 54352362570139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (54352362570139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27176181285068 + 27176181285069.

It is an arithmetic number, because the mean of its divisors is an integer number (27176181285069).

Almost surely, 254352362570137 is an apocalyptic number.

It is an amenable number.

54352362570137 is a deficient number, since it is larger than the sum of its proper divisors (1).

54352362570137 is an equidigital number, since it uses as much as digits as its factorization.

54352362570137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15876000, while the sum is 53.

The spelling of 54352362570137 in words is "fifty-four trillion, three hundred fifty-two billion, three hundred sixty-two million, five hundred seventy thousand, one hundred thirty-seven".