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5435313454453 is a prime number
BaseRepresentation
bin100111100011000000111…
…1011010111110101110101
3201020121111100011212000111
41033012001323113311311
51203023010221020303
615320540514343021
71100455064033641
oct117060173276565
921217440155014
105435313454453
111806115823963
1273949758aa71
1330571785508c
1414b0db92bc21
15965b9465b6d
hex4f181ed7d75

5435313454453 has 2 divisors, whose sum is σ = 5435313454454. Its totient is φ = 5435313454452.

The previous prime is 5435313454451. The next prime is 5435313454469. The reversal of 5435313454453 is 3544543135345.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4842033013444 + 593280441009 = 2200462^2 + 770247^2 .

It is a cyclic number.

It is not a de Polignac number, because 5435313454453 - 21 = 5435313454451 is a prime.

Together with 5435313454451, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 5435313454397 and 5435313454406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5435313454451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717656727226 + 2717656727227.

It is an arithmetic number, because the mean of its divisors is an integer number (2717656727227).

Almost surely, 25435313454453 is an apocalyptic number.

It is an amenable number.

5435313454453 is a deficient number, since it is larger than the sum of its proper divisors (1).

5435313454453 is an equidigital number, since it uses as much as digits as its factorization.

5435313454453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960000, while the sum is 49.

Adding to 5435313454453 its reverse (3544543135345), we get a palindrome (8979856589798).

The spelling of 5435313454453 in words is "five trillion, four hundred thirty-five billion, three hundred thirteen million, four hundred fifty-four thousand, four hundred fifty-three".