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54355037774837 is a prime number
BaseRepresentation
bin11000101101111100001001…
…01101111110001111110101
321010110021212001001122100012
430112332010231332033311
524111023104132243322
6311334205403030005
714310010335626552
oct1426760455761765
9233407761048305
1054355037774837
1116356929877888
12611a45420b305
132443872a13687
14d5cb254b1a29
15643d75087ae2
hex316f84b7e3f5

54355037774837 has 2 divisors, whose sum is σ = 54355037774838. Its totient is φ = 54355037774836.

The previous prime is 54355037774809. The next prime is 54355037774839. The reversal of 54355037774837 is 73847773055345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46498951932196 + 7856085842641 = 6819014^2 + 2802871^2 .

It is a cyclic number.

It is not a de Polignac number, because 54355037774837 - 214 = 54355037758453 is a prime.

Together with 54355037774839, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54355037774839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27177518887418 + 27177518887419.

It is an arithmetic number, because the mean of its divisors is an integer number (27177518887419).

Almost surely, 254355037774837 is an apocalyptic number.

It is an amenable number.

54355037774837 is a deficient number, since it is larger than the sum of its proper divisors (1).

54355037774837 is an equidigital number, since it uses as much as digits as its factorization.

54355037774837 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1037232000, while the sum is 68.

The spelling of 54355037774837 in words is "fifty-four trillion, three hundred fifty-five billion, thirty-seven million, seven hundred seventy-four thousand, eight hundred thirty-seven".