Search a number
-
+
5439701513 is a prime number
BaseRepresentation
bin1010001000011101…
…10100001000001001
3112001002202110122102
411010032310020021
542120030422023
62255435403145
7251541462041
oct50416641011
915032673572
105439701513
11234162a294
1210798b34b5
13688c90bbc
1439863c721
1521c85d628
hex1443b4209

5439701513 has 2 divisors, whose sum is σ = 5439701514. Its totient is φ = 5439701512.

The previous prime is 5439701479. The next prime is 5439701551. The reversal of 5439701513 is 3151079345.

5439701513 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (5439701551) can be obtained adding 5439701513 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3447686089 + 1992015424 = 58717^2 + 44632^2 .

It is a cyclic number.

It is not a de Polignac number, because 5439701513 - 210 = 5439700489 is a prime.

It is not a weakly prime, because it can be changed into another prime (5439701563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2719850756 + 2719850757.

It is an arithmetic number, because the mean of its divisors is an integer number (2719850757).

Almost surely, 25439701513 is an apocalyptic number.

It is an amenable number.

5439701513 is a deficient number, since it is larger than the sum of its proper divisors (1).

5439701513 is an equidigital number, since it uses as much as digits as its factorization.

5439701513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56700, while the sum is 38.

The square root of 5439701513 is about 73754.3321642871. The cubic root of 5439701513 is about 1758.6997016941.

The spelling of 5439701513 in words is "five billion, four hundred thirty-nine million, seven hundred one thousand, five hundred thirteen".