5441255503 has 2 divisors, whose sum is σ = 5441255504. Its totient is φ = 5441255502.

The previous prime is 5441255461. The next prime is 5441255507. The reversal of 5441255503 is 3055521445.

5441255503 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5441255503 - 2¹³ = 5441247311 is a prime.

It is a super-2 number, since 2×5441255503² = 59214522897855566018, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5441255507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2720627751 + 2720627752.

It is an arithmetic number, because the mean of its divisors is an integer number (2720627752).

Almost surely, 2^5441255503 is an apocalyptic number.

5441255503 is a deficient number, since it is larger than the sum of its proper divisors (1).

5441255503 is an equidigital number, since it uses as much as digits as its factorization.

5441255503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60000, while the sum is 34.

The square root of 5441255503 is about 73764.8663185937. The cubic root of 5441255503 is about 1758.8671582806.

Adding to 5441255503 its reverse (3055521445), we get a palindrome (8496776948).

The spelling of 5441255503 in words is "five billion, four hundred forty-one million, two hundred fifty-five thousand, five hundred three".