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54413521041197 is a prime number
BaseRepresentation
bin11000101111101001000101…
…00101111011011100101101
321010122212210211122101200102
430113310202211323130231
524113002342341304242
6311421120530240445
714314150530323363
oct1427644245733455
9233585724571612
1054413521041197
111637971008546a
126129856126125
13244923316cb26
14d618b2747633
15645649587e32
hex317d2297b72d

54413521041197 has 2 divisors, whose sum is σ = 54413521041198. Its totient is φ = 54413521041196.

The previous prime is 54413521041167. The next prime is 54413521041223. The reversal of 54413521041197 is 79114012531445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52573317556516 + 1840203484681 = 7250746^2 + 1356541^2 .

It is a cyclic number.

It is not a de Polignac number, because 54413521041197 - 216 = 54413520975661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54413521041167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27206760520598 + 27206760520599.

It is an arithmetic number, because the mean of its divisors is an integer number (27206760520599).

Almost surely, 254413521041197 is an apocalyptic number.

It is an amenable number.

54413521041197 is a deficient number, since it is larger than the sum of its proper divisors (1).

54413521041197 is an equidigital number, since it uses as much as digits as its factorization.

54413521041197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 604800, while the sum is 47.

The spelling of 54413521041197 in words is "fifty-four trillion, four hundred thirteen billion, five hundred twenty-one million, forty-one thousand, one hundred ninety-seven".