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544400531341 is a prime number
BaseRepresentation
bin1111110110000001100…
…11001101111110001101
31221001012012122101220021
413323000303031332031
532404413014000331
61054032200422141
754221516110522
oct7730063157615
91831165571807
10544400531341
1119a9739a88a7
1289612777951
133c44babb124
141c4c6007149
15e263b0b211
hex7ec0ccdf8d

544400531341 has 2 divisors, whose sum is σ = 544400531342. Its totient is φ = 544400531340.

The previous prime is 544400531327. The next prime is 544400531453. The reversal of 544400531341 is 143135004445.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 462230015625 + 82170515716 = 679875^2 + 286654^2 .

It is a cyclic number.

It is not a de Polignac number, because 544400531341 - 221 = 544398434189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 544400531297 and 544400531306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544400534341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272200265670 + 272200265671.

It is an arithmetic number, because the mean of its divisors is an integer number (272200265671).

Almost surely, 2544400531341 is an apocalyptic number.

It is an amenable number.

544400531341 is a deficient number, since it is larger than the sum of its proper divisors (1).

544400531341 is an equidigital number, since it uses as much as digits as its factorization.

544400531341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 544400531341 its reverse (143135004445), we get a palindrome (687535535786).

The spelling of 544400531341 in words is "five hundred forty-four billion, four hundred million, five hundred thirty-one thousand, three hundred forty-one".