Base | Representation |
---|---|
bin | 1111110110000010111… |
… | …00011101001001011111 |
3 | 1221001012221222121112002 |
4 | 13323001130131021133 |
5 | 32404423300411112 |
6 | 1054033224232515 |
7 | 54222010022663 |
oct | 7730134351137 |
9 | 1831187877462 |
10 | 544411341407 |
11 | 19a97a01163a |
12 | 8961630b73b |
13 | 3c45110460b |
14 | 1c4c761c8a3 |
15 | e264a441c2 |
hex | 7ec171d25f |
544411341407 has 2 divisors, whose sum is σ = 544411341408. Its totient is φ = 544411341406.
The previous prime is 544411341379. The next prime is 544411341421. The reversal of 544411341407 is 704143114445.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 544411341407 - 210 = 544411340383 is a prime.
It is a super-2 number, since 2×5444113414072 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (544411341907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272205670703 + 272205670704.
It is an arithmetic number, because the mean of its divisors is an integer number (272205670704).
Almost surely, 2544411341407 is an apocalyptic number.
544411341407 is a deficient number, since it is larger than the sum of its proper divisors (1).
544411341407 is an equidigital number, since it uses as much as digits as its factorization.
544411341407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 107520, while the sum is 38.
The spelling of 544411341407 in words is "five hundred forty-four billion, four hundred eleven million, three hundred forty-one thousand, four hundred seven".
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