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544546102117 is a prime number
BaseRepresentation
bin1111110110010010111…
…10100001101101100101
31221001120100120011110111
413323021132201231211
532410212300231432
61054054440453021
754225234332233
oct7731136415545
91831510504414
10544546102117
1119aa39095326
128965347a171
133c472cc8c94
141c4db49b953
15e2717b3347
hex7ec97a1b65

544546102117 has 2 divisors, whose sum is σ = 544546102118. Its totient is φ = 544546102116.

The previous prime is 544546102099. The next prime is 544546102129. The reversal of 544546102117 is 711201645445.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 543890025121 + 656076996 = 737489^2 + 25614^2 .

It is a cyclic number.

It is not a de Polignac number, because 544546102117 - 211 = 544546100069 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 544546102117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544546102147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272273051058 + 272273051059.

It is an arithmetic number, because the mean of its divisors is an integer number (272273051059).

Almost surely, 2544546102117 is an apocalyptic number.

It is an amenable number.

544546102117 is a deficient number, since it is larger than the sum of its proper divisors (1).

544546102117 is an equidigital number, since it uses as much as digits as its factorization.

544546102117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 40.

The spelling of 544546102117 in words is "five hundred forty-four billion, five hundred forty-six million, one hundred two thousand, one hundred seventeen".