Base | Representation |
---|---|
bin | 1111110111010000100… |
… | …10110011001000010111 |
3 | 1221002220101102110121222 |
4 | 13323220102303020113 |
5 | 32412242124341211 |
6 | 1054222030200555 |
7 | 54244113042203 |
oct | 7735022631027 |
9 | 1832811373558 |
10 | 545063121431 |
11 | 1a0183a16614 |
12 | 8977865315b |
13 | 3c52615c87a |
14 | 1c54a003b03 |
15 | e2a1d8e1db |
hex | 7ee84b3217 |
545063121431 has 2 divisors, whose sum is σ = 545063121432. Its totient is φ = 545063121430.
The previous prime is 545063121403. The next prime is 545063121437. The reversal of 545063121431 is 134121360545.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 545063121431 - 218 = 545062859287 is a prime.
It is a super-2 number, since 2×5450631214312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 545063121391 and 545063121400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (545063121437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272531560715 + 272531560716.
It is an arithmetic number, because the mean of its divisors is an integer number (272531560716).
Almost surely, 2545063121431 is an apocalyptic number.
545063121431 is a deficient number, since it is larger than the sum of its proper divisors (1).
545063121431 is an equidigital number, since it uses as much as digits as its factorization.
545063121431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 545063121431 its reverse (134121360545), we get a palindrome (679184481976).
The spelling of 545063121431 in words is "five hundred forty-five billion, sixty-three million, one hundred twenty-one thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •