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545063121437 is a prime number
BaseRepresentation
bin1111110111010000100…
…10110011001000011101
31221002220101102110122012
413323220102303020131
532412242124341222
61054222030201005
754244113042212
oct7735022631035
91832811373565
10545063121437
111a0183a1661a
1289778653165
133c52615c883
141c54a003b09
15e2a1d8e1e2
hex7ee84b321d

545063121437 has 2 divisors, whose sum is σ = 545063121438. Its totient is φ = 545063121436.

The previous prime is 545063121431. The next prime is 545063121481. The reversal of 545063121437 is 734121360545.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 426051231076 + 119011890361 = 652726^2 + 344981^2 .

It is a cyclic number.

It is not a de Polignac number, because 545063121437 - 28 = 545063121181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 545063121394 and 545063121403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (545063121431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272531560718 + 272531560719.

It is an arithmetic number, because the mean of its divisors is an integer number (272531560719).

Almost surely, 2545063121437 is an apocalyptic number.

It is an amenable number.

545063121437 is a deficient number, since it is larger than the sum of its proper divisors (1).

545063121437 is an equidigital number, since it uses as much as digits as its factorization.

545063121437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 545063121437 in words is "five hundred forty-five billion, sixty-three million, one hundred twenty-one thousand, four hundred thirty-seven".