Base | Representation |
---|---|
bin | 110010110001010010… |
… | …110011100000010111 |
3 | 12012201011220102122121 |
4 | 302301102303200113 |
5 | 1343121102314333 |
6 | 41013214240411 |
7 | 3636624145546 |
oct | 626122634027 |
9 | 165634812577 |
10 | 54514104343 |
11 | 211348774a6 |
12 | a6947b6107 |
13 | 51aa04429a |
14 | 28d206c15d |
15 | 1640d1c32d |
hex | cb14b3817 |
54514104343 has 2 divisors, whose sum is σ = 54514104344. Its totient is φ = 54514104342.
The previous prime is 54514104311. The next prime is 54514104361. The reversal of 54514104343 is 34340141545.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54514104343 - 25 = 54514104311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54514104299 and 54514104308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54514104943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27257052171 + 27257052172.
It is an arithmetic number, because the mean of its divisors is an integer number (27257052172).
Almost surely, 254514104343 is an apocalyptic number.
54514104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
54514104343 is an equidigital number, since it uses as much as digits as its factorization.
54514104343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 54514104343 its reverse (34340141545), we get a palindrome (88854245888).
The spelling of 54514104343 in words is "fifty-four billion, five hundred fourteen million, one hundred four thousand, three hundred forty-three".
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