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545212515047 is a prime number
BaseRepresentation
bin1111110111100010011…
…00101100001011100111
31221010021210112110010212
413323301030230023213
532413043400440142
61054244524210035
754250605625124
oct7736114541347
91833253473125
10545212515047
111a0250284212
12897ba69991b
133c54b0a8765
141c561bb174b
15e2b004dd82
hex7ef132c2e7

545212515047 has 2 divisors, whose sum is σ = 545212515048. Its totient is φ = 545212515046.

The previous prime is 545212514999. The next prime is 545212515049. The reversal of 545212515047 is 740515212545.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 545212515047 - 224 = 545195737831 is a prime.

Together with 545212515049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 545212514995 and 545212515013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (545212515049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272606257523 + 272606257524.

It is an arithmetic number, because the mean of its divisors is an integer number (272606257524).

Almost surely, 2545212515047 is an apocalyptic number.

545212515047 is a deficient number, since it is larger than the sum of its proper divisors (1).

545212515047 is an equidigital number, since it uses as much as digits as its factorization.

545212515047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 280000, while the sum is 41.

The spelling of 545212515047 in words is "five hundred forty-five billion, two hundred twelve million, five hundred fifteen thousand, forty-seven".