Base | Representation |
---|---|
bin | 1111110111110000101… |
… | …00100010010001010101 |
3 | 1221010121010101112022021 |
4 | 13323320110202101111 |
5 | 32413314443341432 |
6 | 1054304433333141 |
7 | 54253556423104 |
oct | 7737024422125 |
9 | 1833533345267 |
10 | 545332012117 |
11 | 1a0301782122 |
12 | 898327071b1 |
13 | 3c569a87799 |
14 | 1c5739da03b |
15 | e2ba7a5697 |
hex | 7ef8522455 |
545332012117 has 2 divisors, whose sum is σ = 545332012118. Its totient is φ = 545332012116.
The previous prime is 545332012051. The next prime is 545332012139. The reversal of 545332012117 is 711210233545.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 393613192996 + 151718819121 = 627386^2 + 389511^2 .
It is a cyclic number.
It is not a de Polignac number, because 545332012117 - 215 = 545331979349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (545332015117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272666006058 + 272666006059.
It is an arithmetic number, because the mean of its divisors is an integer number (272666006059).
Almost surely, 2545332012117 is an apocalyptic number.
It is an amenable number.
545332012117 is a deficient number, since it is larger than the sum of its proper divisors (1).
545332012117 is an equidigital number, since it uses as much as digits as its factorization.
545332012117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 34.
The spelling of 545332012117 in words is "five hundred forty-five billion, three hundred thirty-two million, twelve thousand, one hundred seventeen".
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