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545443015324261 is a prime number
BaseRepresentation
bin111110000000100111101100…
…1001011000111001001100101
32122112020211202120010000220211
41330001033121023013021211
51032443014243410334021
65212021021222255421
7222613646252064325
oct17401173113071145
92575224676100824
10545443015324261
111488820a153155a
1251212616287571
131a547095331922
1498998232c3285
15430d357cdb3e1
hex1f013d92c7265

545443015324261 has 2 divisors, whose sum is σ = 545443015324262. Its totient is φ = 545443015324260.

The previous prime is 545443015324219. The next prime is 545443015324271. The reversal of 545443015324261 is 162423510344545.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 526389737944225 + 19053277380036 = 22943185^2 + 4365006^2 .

It is a cyclic number.

It is not a de Polignac number, because 545443015324261 - 223 = 545443006935653 is a prime.

It is a super-2 number, since 2×5454430153242612 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (545443015324201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272721507662130 + 272721507662131.

It is an arithmetic number, because the mean of its divisors is an integer number (272721507662131).

Almost surely, 2545443015324261 is an apocalyptic number.

It is an amenable number.

545443015324261 is a deficient number, since it is larger than the sum of its proper divisors (1).

545443015324261 is an equidigital number, since it uses as much as digits as its factorization.

545443015324261 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912000, while the sum is 49.

The spelling of 545443015324261 in words is "five hundred forty-five trillion, four hundred forty-three billion, fifteen million, three hundred twenty-four thousand, two hundred sixty-one".