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54611523343441 is a prime number
BaseRepresentation
bin11000110101011001111000…
…11100110001010001010001
321011100210212221220112001001
430122230330130301101101
524124223344433442231
6312052104254542001
714334360313164601
oct1432547434612121
9234323787815031
1054611523343441
1116445687231789
1261600b4807901
132461ac963c80c
14d6b2d73acc01
1564a887451b61
hex31ab3c731451

54611523343441 has 2 divisors, whose sum is σ = 54611523343442. Its totient is φ = 54611523343440.

The previous prime is 54611523343423. The next prime is 54611523343451. The reversal of 54611523343441 is 14434332511645.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52182925250625 + 2428598092816 = 7223775^2 + 1558396^2 .

It is a cyclic number.

It is not a de Polignac number, because 54611523343441 - 27 = 54611523343313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54611523343391 and 54611523343400.

It is not a weakly prime, because it can be changed into another prime (54611523343451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27305761671720 + 27305761671721.

It is an arithmetic number, because the mean of its divisors is an integer number (27305761671721).

Almost surely, 254611523343441 is an apocalyptic number.

It is an amenable number.

54611523343441 is a deficient number, since it is larger than the sum of its proper divisors (1).

54611523343441 is an equidigital number, since it uses as much as digits as its factorization.

54611523343441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2073600, while the sum is 46.

The spelling of 54611523343441 in words is "fifty-four trillion, six hundred eleven billion, five hundred twenty-three million, three hundred forty-three thousand, four hundred forty-one".