Base | Representation |
---|---|
bin | 11000110101011001111000… |
… | …11100110001010001011011 |
3 | 21011100210212221220112001102 |
4 | 30122230330130301101123 |
5 | 24124223344433442301 |
6 | 312052104254542015 |
7 | 14334360313164614 |
oct | 1432547434612133 |
9 | 234323787815042 |
10 | 54611523343451 |
11 | 16445687231798 |
12 | 61600b480790b |
13 | 2461ac963c819 |
14 | d6b2d73acc0b |
15 | 64a887451b6b |
hex | 31ab3c73145b |
54611523343451 has 2 divisors, whose sum is σ = 54611523343452. Its totient is φ = 54611523343450.
The previous prime is 54611523343441. The next prime is 54611523343459. The reversal of 54611523343451 is 15434332511645.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54611523343451 - 218 = 54611523081307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54611523343396 and 54611523343405.
It is not a weakly prime, because it can be changed into another prime (54611523343459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27305761671725 + 27305761671726.
It is an arithmetic number, because the mean of its divisors is an integer number (27305761671726).
Almost surely, 254611523343451 is an apocalyptic number.
54611523343451 is a deficient number, since it is larger than the sum of its proper divisors (1).
54611523343451 is an equidigital number, since it uses as much as digits as its factorization.
54611523343451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592000, while the sum is 47.
The spelling of 54611523343451 in words is "fifty-four trillion, six hundred eleven billion, five hundred twenty-three million, three hundred forty-three thousand, four hundred fifty-one".
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