Base | Representation |
---|---|
bin | 110010111100101100… |
… | …111100011101010101 |
3 | 12020012112001122112210 |
4 | 302330230330131111 |
5 | 1344014102144013 |
6 | 41044212504033 |
7 | 3644440062345 |
oct | 627454743525 |
9 | 166175048483 |
10 | 54705506133 |
11 | 212229174a3 |
12 | a72891b019 |
13 | 520a8aaa95 |
14 | 290d652d25 |
15 | 1652a28cc3 |
hex | cbcb3c755 |
54705506133 has 64 divisors (see below), whose sum is σ = 80764895232. Its totient is φ = 32796042240.
The previous prime is 54705506129. The next prime is 54705506147. The reversal of 54705506133 is 33160550745.
It is not a de Polignac number, because 54705506133 - 22 = 54705506129 is a prime.
It is a super-2 number, since 2×547055061332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54705506091 and 54705506100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54705506123) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 28329178 + ... + 28331108.
It is an arithmetic number, because the mean of its divisors is an integer number (1261951488).
Almost surely, 254705506133 is an apocalyptic number.
54705506133 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
54705506133 is a deficient number, since it is larger than the sum of its proper divisors (26059389099).
54705506133 is a wasteful number, since it uses less digits than its factorization.
54705506133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2274.
The product of its (nonzero) digits is 189000, while the sum is 39.
The spelling of 54705506133 in words is "fifty-four billion, seven hundred five million, five hundred six thousand, one hundred thirty-three".
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