Base | Representation |
---|---|
bin | 1101000010111… |
… | …1010101000101 |
3 | 10210222001110202 |
4 | 3100233111011 |
5 | 103002013223 |
6 | 5232500245 |
7 | 1233052661 |
oct | 320572505 |
9 | 123861422 |
10 | 54719813 |
11 | 28984895 |
12 | 163aa685 |
13 | b44b7b5 |
14 | 73a58a1 |
15 | 4c0d428 |
hex | 342f545 |
54719813 has 2 divisors, whose sum is σ = 54719814. Its totient is φ = 54719812.
The previous prime is 54719761. The next prime is 54719837. The reversal of 54719813 is 31891745.
54719813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29789764 + 24930049 = 5458^2 + 4993^2 .
It is a cyclic number.
It is not a de Polignac number, because 54719813 - 220 = 53671237 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54719843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27359906 + 27359907.
It is an arithmetic number, because the mean of its divisors is an integer number (27359907).
Almost surely, 254719813 is an apocalyptic number.
It is an amenable number.
54719813 is a deficient number, since it is larger than the sum of its proper divisors (1).
54719813 is an equidigital number, since it uses as much as digits as its factorization.
54719813 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 30240, while the sum is 38.
The square root of 54719813 is about 7397.2841637996. The cubic root of 54719813 is about 379.6483658504.
The spelling of 54719813 in words is "fifty-four million, seven hundred nineteen thousand, eight hundred thirteen".
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